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6u^2-42u-48=0
a = 6; b = -42; c = -48;
Δ = b2-4ac
Δ = -422-4·6·(-48)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-54}{2*6}=\frac{-12}{12} =-1 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+54}{2*6}=\frac{96}{12} =8 $
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